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5x^2-115x+300=0
a = 5; b = -115; c = +300;
Δ = b2-4ac
Δ = -1152-4·5·300
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-115)-85}{2*5}=\frac{30}{10} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-115)+85}{2*5}=\frac{200}{10} =20 $
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